Can someone please help me?​

9514 1404 393

Step-by-step explanation:

I like a graphing calculator for creating graphs. Here, each inequality is in "slope-intercept" form, so the y-intercepts are easily located (+8 and -4).

The slope (x-coefficient) is the "rise" divided by the "run". The boundary line of the first inequality has a rise of -1 for each run of 3 to the right. The second rises 5 units for each 3 to the right. Starting from the y-intercept, additional points to plot are easily found.

Of course, the boundary line is solid for y ≥ ( ), and is dashed for y < ( ). The shading will be above the line (for higher y-values) for the first inequality, and below the line (for lower y-values) for the second inequality. That puts the double-shaded solution area in the right-side quadrant of the X where the lines cross.

There are an infinite number of solution points to choose from. One of them is (12, 5). Points with an x-value that is a multiple of 3 will be easiest to substitute into the inequalities to check.

  5 ≥ (-1/3)(12) +8   ⇒   5 ≥ 4 . . . true

  5 < (5/3)(12) -4   ⇒   5 < 16 . . . true

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.

part a: 1.08

part b: 27.59