Please help me with 6-7 / 10 points

6) Axis of symmetry x=1. Vertex at (5,1)

7) Axis of symmetry x=1. Vertex at (1,2). y-intercept at y = -1

Step-by-step explanation:

There is an equation to find the axis of symmetry of a quadratic function and is given by:

Knowing that the standard form of a quadratic equation is:

The axis of symmetry is:

(1)

(6)

The quadratic equation of the first problem is:

Then, using equation (1) the axis of symmetry will be:

We need to use this value of x to find the vertex;

The vertex is (5,1)

Therefore, we disagree with Ahmed. The axis of symmetry is x = 1 and the vertex is in the point (5,1).

(7)

We can use the same method here. The function is:

The axis of symmetry is:

The vertex is:

So the vertex is (1,2)

We need to evaluate the function at x = 0 to get the y-intercept value.

Therefore, the y-intercept is at y = -1.

I hope it helps you!

, ; dcbsdkmnld

step-by-step explanation:

the answer will be b x² +x-1

step-by-step explanation: