Two triangles aresimilar. The length of a side of one of the triangle is 6times that of the corresponding sides of the other. Find the ratio of the perimeter and the area of the triangle

--- of perimeters

--- of areas

Step-by-step explanation:

Given

Represent the sides of the first triangle with x, y and z

The sides of the second triangle will be 6x, 6y and 6z

Solving (a): Ratio of perimeter.

The perimeter of the first is:

The perimeter of the second is:

Factorize:

The ratio is:

Cancel out x + y + z

Solving (a): Ratio of Areas.

If the height of the first is h and the base is b.

The height of the second will be 6h and the base, 6b.

The area of the first is:

The area of the second is:

The ratio is:

Divide by 0.5bh

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

what is the your question?