From a boat ont he lake, the angle of elevation to the top of a cliff is 11° 50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)

328 feet

Step-by-step explanation:

From a boat ont he lake, the angle of elevation to the top of a cliff is 11° 50'. If the base of the cliff is 1568 feet from the boat, how high is the cliff (to the nearest foot)

Step 1

Note that

that 11°50' is just 11 degrees and 50 minutes

60 minutes = 1 degree,

thus 50 minutes = x degree

50/60 degrees

= 0.83°

Hence: 11°50' = 11.83°.

Step 2

We solve using Trigonometric function of tan

tan theta = Opposite/Adjacent

theta = 11.83°

Adjacent = 1568 feet

Opposite = Height of the cliff = x

tan 11.83° = x/1568

Cross Multiply

x = tan 11.83 × 1568

x = 328.429195 feet

Approximately = 328 feet

The height of the cliff is 328 feet

stethere all not eveanp-by-step explanation:

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4