a quadratic patterns has a second term equal to 1,a third term equal to -6 and fifth term equal to -14 .hence or otherwise calculate the first term of the pattern​

first term of the pattern​ (T₁) : 10

Step-by-step explanation:

T₁  ;    1 ;    -6 ;   T₄ ;    -14  

1-T₁  ;  -6-1   ; T₄-(-6)  ; -14 -T₄    (First Tₙ-Tₙ₋₁)

-8+T₁  = T₄+13 = -2T₄-20            (2nd Tₙ-Tₙ₋₁ is constant)

T₄+13 = -2T₄-20          3T₄ = -33          T₄ = -11

-8+T₁  = T₄+13         -8 + T₁ = -11 + 13 = 2

T₁ = 10

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles