Given the function F (x) = x2 -2x -5 determine the average rate of change of the function over the interval -5 < x <6.

1

Step-by-step explanation:

Here f(x) = x^2 - 2x - 5, which at x - -5 is 25 +10 - 5 = 30 and at x = 6 is 19.

The average value of a function f(x) over an interval [a, b] is

                  f(b) - f(a)

ave. val. =

                     b - a

which in this particular case is

                     19 - 30

ave. val. = = -11/11 = 1

                     6 - (-5)

The average value of this function f(x) = x^2 - 2x - 5 on [-5, 6] is 1.

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hope this .. : d

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}