What is the solution to the system of equations below?

{3x+4y=(-2)
{2x-4y=(-8)

x = -2 , y = 1

Step-by-step explanation:

add the terms :

3x+2x+4y-4y = -2-8

5x = -10

x = -2

now that x = -2 , plug its value into any of the two equations (we'll take the first)

3*-2 +4y = -2

4y = 4

y = 1

x = -2

y = 1

Step-by-step explanation:

{3x+4y=(-2)

{2x-4y=(-8)

{4y = -2 - 3x

{2x - 4y = -8

Substitute the value of 4y in 2x - 4y = -8

2x - (-2 - 3x) = -8

x= - 2

Substitute the value of x into 2x - 4y = -8

= 2x (-2) - 4y = -8

y = 1

answer: 2 and 1

step-by-step explanation: got this question

7. d. 64

8. i. 32

9. c. 125

10. j. none of the above

11. d. 81

12. i. 216

13. e. none of the above

14. g. 240

15. e. none of the above

16. g. 32

17.   e. none of the above