Find two consecutive odd integers whose product is equal to 63​

If you need to see a systematic solution, let the 2 numbers be n and n + 2.

n(n + 2) = 63

n2 + 2n - 63 = 0

(n - 7)(n + 9) = 0

n = 7 or -9

If n = 7, then n + 2 = 9

If n = -9, then n + 2 = -7

This is based on knowledge of composite numbers: 7 times 9 = 63.

The only other pair of numbers satisfying this is -7 and -9

A bit confusing but hopes that helps out somewhat

nothjing

step-by-step explanation:

the data of the detroit pistons in numerical order from least to greatest is 0.30, 0.37, 0.55, 0.62, 0.69, 0.72, 0.73, 0.75, 0.77, 0.78, 0.80, 0.81, 0.81, 0.83, 0.84, 0.89

the data of the miami heat in numerical order from least to greatest is 0.50, 0.50, 0.56, 0.57, 0.67, 0.72, 0.72, 0.72, 0.75, 0.75, 0.76, 0.81, 0.82, 0.90, 1.00, 1.00

the detroit pistons median : 1.52

the miami heat median: 1.47

the iqr of this data is 0.05