Robert owns a doggy hotel. This is like a kennel but much fancier. Last friday the 14th he had 35 dogs that ate 3/8 of a pound of food. On friday the 7th he had 27 dogs that ate 1/2 of a pound each. which friday did he need more food and how many more pounds

the 7th

0.007805 or  59 / 756

Step-by-step explanation:

To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.

to do this, divide the total pounds by the number of dogs

on the 14th

3/8 ÷ 35 =

3/8 x 1/35 = 3/280

on the 7th

1/2 ÷ 27 =

1/2 x 1/27 = 1/54

to determine which fraction is larger multiply each by 100 to determine its percent

3/280 x 100 = 1.071

1/54 x 100 = 1.852

1/54 is larger. Thus, more pounds was needed on Friday the 7th

the difference between these fractions should be determined  

-

= = 59 / 756

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: