.necesito resolver estas operaciones con factorial ayuda por favor - A= (4ǃ+2ǃ+3ǃ)/(3ǃ+2ǃ)

2. (6ǃ-4ǃ)/2ǃ

2ǃx3ǃx4ǃ/(5ǃ+4ǃ)

R = 10ǃx8ǃ/(6ǃ+5ǃ)

((x+5)ǃ(x+3)ǃ)/((x+4)ǃ+(x+3)ǃ)=6ǃ

A. 4

B. 348

C. 2

D. 174182400

E. x = 2

Step-by-step explanation:

Given - A= (4ǃ+2ǃ+3ǃ)/(3ǃ+2ǃ)

             B = (6ǃ-4ǃ)/2ǃ

             C = 2ǃx3ǃx4ǃ/(5ǃ+4ǃ)

             D = 10ǃx8ǃ/(6ǃ+5ǃ)

             E -  ((x+5)ǃ(x+3)ǃ)/((x+4)ǃ+(x+3)ǃ)=6ǃ

Proof -

A.

(4! + 2! + 3! )/ (3! + 2!) = [4×3×2! + 2! + 3×2!] / [3×2! + 2!]

                                  = 2! [ 4×3 + 1 + 3] / 2! [3 + 1]

                                  = [12 + 1 + 3] / [4]

                                  = [16] / [4] = 4

⇒(4! + 2! + 3! )/ (3! + 2!) = 4

B.

(6ǃ-4ǃ)/2ǃ = [6×5×4! - 4!] / 2!

              = 4! [6×5 - 1] / 2!

              = 4×3×2! [ 30 - 1] / 2!

              = 12 [29] = 348

⇒(6ǃ-4ǃ)/2ǃ = 348

C.

2ǃx3ǃx4ǃ/(5ǃ+4ǃ) = 2!×3!×4! / [ 5×4! + 4!]

                         = 2!×3!×4! / 4! [ 5 + 1]

                         = (2×1) × (3×2×1) / 6

                         = 12 / 6 = 2

⇒2ǃx3ǃx4ǃ/(5ǃ+4ǃ) = 2

D.

10ǃx8ǃ/(6ǃ+5ǃ) = 10!×8! / [ 6×5! + 5!]

                      = (10×9×8×7×6×5×4×3×2×1) ×(8×7×6×5!) / 5! [6 + 1]

                      = (10×9×8×7×6×5×4×3×2×1) ×(8×7×6) / [7]

                      = (10×9×8×7×6×5×4×3×2×1) ×(8×6)

                      = 174182400

⇒10ǃx8ǃ/(6ǃ+5ǃ) = 174182400

E.

((x+5)ǃ(x+3)ǃ)/((x+4)ǃ+(x+3)ǃ)=6ǃ

[(x+5)(x+4)(x+3)! (x+3)!] / [ (x+4)(x+3)! + (x+3)! ] = 6!

[(x+5)(x+4)(x+3)! (x+3)!] / (x+3)!  [ (x+4)+ 1] = 6!

[(x+5)(x+4)(x+3)! / (  [ x+ 5 ] = 6!

(x+4)(x+3)! = 6!

(x+4)! = 6!

x+ 4 = 6

x = 6 - 4

x = 2

Note :

x! = x(x-1)(x-2)(4)(3)(2)(1)

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form