HELP ME ASAP.
This question is from Algebra Nation.

Step-by-step explanation:

vertex form   y = (x-h)^2 + k      and vertex is at  ( h, k)

the problem has   y = x^2 + 5

then  y = (x - 0)^2 + 5    the vertex is at  ( 0 , 5)  

shift that to the right 3 , then

y = ( x - 3)^2 + 5     now the vertex is at (3,5)    nice

now shift to the left 10  ( to the left is sooner, to the right is later , that why we subtract to go right and add to go left)

y = ( x + 10 )^2 + 5    now the vertex is at ( -10, 5 )    or shifted 10 left

:)

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step-by-step explanation: