Among all pairs of numbers whose difference is 6, find a pair whose product is as small as possible. What is the minimum produc The pair of numbers whose difference is 6 and whose product is as small as possible is ? ​

pairs of numbers is 3,-3

Step-by-step explanation:

The computation is shown below:

Let us assume a and b are the pairs of the numbers whose difference is 6

i.e.

a - b = 6

a = 6 + b

So

f = ab

f = (6 + b)b is minimum

Now

d ÷ db (6+ b)b = 0

(6+ b) + b = 0

2b = -6

b = -3

Now

a  = 6 + b

= 3

So pairs of numbers is 3,-3

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

⭐⭐

answer: .64

step-by-step explanation

set up the formula for standard deviation for this set of numbers, then simplify