How to prove this using trig identities? (Tan B + Cot B)^2 = sec^2B + csc^2B

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Step-by-step explanation:

tanB + cotB = (sinB)/(cosB) + (cosB)/(sinB)

                      = (sin2B + cos2B)/[(cosB)(sinB)]

                       = 1/[(cosB)(sinB)]

                        = (1/cosB)(1/sinB)

                        = (secB)(cscB)

b. x + 1

step-by-step explanation:

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answer

false

explanation

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