1 1/3 times 2/3 times 5 1/3

Find the maximum value of p= 4x + 5y subject to the following constraints :

Need solving this 2nd limit problem.

Astudent draws two parabolas both parabolas cross the x axis at (-4,0) and (6,0) the y intercept of the first parabolas is (0,-12). the y intercept of the second parabola is (0,-24) what is the positive difference between the a values for the two functions that describe the parabolas