Ook at these three equations. 6(x−2)=6x−3
2(x−3)=2x−6
3(x−2)=x−6
Which of the equations has exactly one solution?

third

Step-by-step explanation:

3(x-2)=x-6 would be correct

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

g

step-by-step explanation: