Which set of integers is ordered from least to greatest -13 , 4, 0, -8 -5 , -2, 3, 1 -12 , -18 , -4 , 7 -15, 6 , -9 , -21

Given:

The set of integers in the options.

-13 , 4, 0, -8

-5 , -2, 3, 1

-12 -18 , -4 , 7

-15, 6 , -9 , -21

To find:

The set of integers that is ordered from least to greatest.

Solution:

We know that the larger negative value is the smaller value and the larger positive value is the greater value.

Ordered from least to greatest means first we need to write the smallest value, write the value larger than and the greatest value occurs at the end.

In option A, we have -13 , 4, 0, -8. Here, 4>0. So, the option A is incorrect.

In option B, we have -5 , -2, 3, 1. Here, 3>1. So, the option B is incorrect.

In option C, we have -12 -18 , -4 , 7 Here, -12>-18. So, the option C is incorrect.

In option D, we have -15, 6 , -9 , -21. Here, 6>-9. So, the option D is incorrect.

Therefore, all the options are incorrect.

it could be a ..idk tho

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this