Need help for question 8 and 9. I need the equation that’s passes through the points!

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points and is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m =

For two points (1, 4) and (5, 8),

m =

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m =

For two points (2, 10) and (6, 4)

m =

m =

By substituting the value of 'm' in the equation,

y =

Since, this line passes through (2, 10)

10 =

b = 10 + 2

b = 12

Therefore, equation of the line will be,

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?