1. In a bag of candy, the probability that an orange candy is chosen is 0.55 and the probably that a green is chosen is 0.45. A person reaches into the bag of candy and chooses two. If X is the number of green candy pieces chosen, find the probability that has 0, 1, or 2 green pieces chosen. (a) Draw a tree diagram showing the possibilities for each outcome.
(b) Create the binomial distribution table for .
Show all your work.

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: