If the area of a square is increased by 69%, then the side of the square is increased by what percent?

Percent Increase in measure of the side of a square = 30%

Step-by-step explanation:

Let the measure of the side of a square = s

Area of the square = (Side)²

                                = s²

If the area of the square is increased by 69%

Area of the new square = s² + 69% of s²

                                        = s² + 0.69s²

                                        = 1.69s²

Therefore, measure of the side of the new square = √(Area of the square)

                                                                                    = √(1.69s²)

                                                                                    = 1.3s

Measure of side of the old square = s

Therefore, increase in measure of the square = 1.3s - s

                                                                            = 0.3s

Percent increase in the measure of the side of the square

=

=

= 30%

step-by-step explanation:

it's 15

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

step-by-step explanation:

formula

x = x1 + p/w(x2 - x1)

let the line segment ab with a(x1,y1) and b(x2,y2)

a point(x,y) divide ab in the ratio, 2: 3 the x coordinate can be written as

x = x1 + p/w(x2 - x1)

here p=2 and w = 2+3

therefore,

x coordinate can be written by using the formula, x= x1 + 2/5(x2 - x1)

similarly y coordinate y = y1 + 2/5(y2 - y1)