Two investments totaling $23,500 produce an annual income of $795. One investment yields 2% per year, while the other yields 7% per year. How much is invested at each rate?

$ 6,500 was invested at 7%, while $ 17,000 was invested at 2%.

Step-by-step explanation:

Given that two investments totaling $ 23,500 produce an annual income of $ 795, and one investment yields 2% per year, while the other yields 7% per year, to determine how much is invested at each rate, the following calculation must be performed:

23,500 x 0.07 + 0 x 0.02 = 1,645

11,750 x 0.07 + 11,750 x 0.02 = 1,057.5

5.875 x 0.07 + 17.625 x 0.02 = 763.75

6,500 x 0.07 + 17,000 x 0.02 = 795

Thus, $ 6,500 was invested at 7%, while $ 17,000 was invested at 2%.

step-by-step explanation:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

step-by-step explanation:

given that megan owns a clothing boutique.

the profits of 2010, 11, are recorded and shown as follows:

years since     2010 0     1     2     3       4       5

profits made in 1000's   39       84     111     120   111     84

we find that profit gradually increases form 2010 to 2013 upto 120,   then starts decreasing.

the profits for 2012 and 2014 are the same while that of 2011 and 2015 are also the same.

this shows that there is symmetry about the line profit = 120000

hence answer is:

a.   since the profit made in 2012 is equal to the profit made in 2014, the profit is           symmetric about the line y = 120,000.

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i think 5 miles per hour

step-by-step explanation: