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The 7th term of Ap is 27 and the 12th term is 47.what is the sequence

3, 7, 11, 15, 19, 23, 27,.......

Step-by-step explanation:

Let the first term and the common difference of the AP be a and d respectively.

Therefore,

a + (7- 1) d = 27

a + 6d = 27

a = 27 - 6d...... (1)

Therefore,

a + (12 - 1) d = 47

a + 11d = 47......(2)

From equations (1) & (2)

27 - 6d + 11d = 47

24 + 5d = 47

5d = 47 - 27

5d = 20

d = 20/5

d = 4

Plug d = 4 in equation (1) we find:

a = 27 - 6*4

a = 27 - 24

a = 3

Therefore,

Thus, the sequence is: 3, 7, 11, 15, 19, 23, 27,.......