The distance an object falls when dropped from a tower varies directly as the square of the time it falls. If the object falls 144 feet in 3 seconds, how far will it fall in 17 seconds? a 4046 ft b 272 ft c 4624 ft d 5202 ft answer is C​

the object will fall 792 feet in 17 seconds

Step-by-step explanation:

first you can do 144 multiplied by 5 because that would be 15 of those seconds next you would do 144 divided by 2 because you only need 2 seconds to reach 17 your answer would be 72 then you would do 720+72=792 so it would fall 792ft in 17 seconds

Step-by-step explanation:

Assuming the Height is denoted by "h" and the time by "t" , h=kt² since h varies as t².

When h=144ft , t=3

k=h/t²

k=144/3²

k= 16

This implies that h=16t² is the relation to be used.

Therefore when t= 17s, h=16*17²

h=4624ft

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !

the answer is 24

step-by-step explanation: