if you stop at random in front of an animal exhibit, What is the probability that you will be looking at monkeys? I put the table chart below

1/10

step-by-step explanation:

| animals | percent of animals |

|    goats    |          16%           |

|    camels    |          4%           |

|    giraffes    |          6%            |

|    llamas    |          6%           |

|   deer    |          1%           |

|   monkeys    |          10%           |

|   birds    |          27%           |

|   reptiles    |          14%           |

|   bears    |          16%           |

( sorry if the table above isnt 100% right or straight ^ )

first you add up all the percents of how much animals are in this exhibit

16 + 4 + 6 + 6 + 1 + 10 + 27 + 14 + 16

= 100 %

then since we are looking for the probability of stopping in front of the monkeys, we take that 100 we got earlier and get the 10% of monkeys from our table

10/100

but since there isnt a 10/100 on the answers we look for something that equals to 10/100 and 1/10 does since you can just times both the 1 and 10 to equal the 10 and 100 you were looking for

1/10

making 1/10 your answer!

hope this helps! and if you need anymore help on this math question just ask me :)

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation:

i can you with this question sweetie!

step-by-step explanation: