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Please show workings and diagrams.​

a) 16.4 kmb) 79°c) 10 km

Step-by-step explanation:

Find the m∠B:

m∠B = (360° - 310°) + 50° = 100°

a)

Find AC using law of cosines:

AC = √(8² + 13² - 28*13*cos 100°) = 16.4 km (rounded)

b)

Find m∠A using law of sines:

16.4/ sin 100 = 13 / sin Am∠A = arcsin (13 sin 100 deg / 16.4) = 51° (rounded)

The bearing of C from A:

180° - (50° + 51°) = 79°

c)

Let the required distance is x:

x/ BC = sin 50°x = BC sin 50°x = 13 sin 50°x ≈ 10 km (rounded)

Oh i'm sorry. didn't see the options