Two students, Matt and Billy , each calculated the volume of a spherical ball with a dime tee of 15 centimeters. Their work is show below

Matt ;

Used diameter of the ball instead of Radius

Step-by-step explanation:

The volume of a sphere is given as :

4/3πr³

Radius, r = diameter / 2

Given that, the diameter = 15 cm ; The Radius = 15 / 2 = 7.5 cm

Matt made an error in his calculation by failing to covert the value of the diameter given to Radius.

By dividing the diameter by 2 = 15 / 2 = 7.5, we obtain the Radius, which is what Billy did in her own calculation.

3.64 deaths an hour.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

ac ≅ ab (given)< cax ≅ < bax   (given)ax ≅ ax (common side)

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

ac ≅ ab (given)< cay ≅ < bay (since < cax ≅ < bax is given and xy is the extension of line ax)ay ≅ ay (common side)

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)