Lee needed to make drapes the length from the floor to the top of the window. The wall beneath the window had the height of 2 2/3 feet and the height of just the window measured 2 3/4 feet. How long do the drapes have to be? the answer needs to be in decimal form

2 2/3 + 2 3/4

convert 2 2/3 to an improper fraction (denomenator times coefficient(the 2) + the numerator all over the denomenator)

3*2 = 6 + 2 = 8/3 ( 2 2/3 = 8/3 you just converted the fraction)

convert 2 3/4 the same way

4*2 = 8+3 = 11/4

now you have

8/3 + 11/4 you have to make the denomenators the same so 4 and 3 both go into 12

what times  3 = 12?  4*3 = 12

8/3 * 4/4 =>32/12 <(you multiply across)(4/4  = 1 so technically you arnt changing the value of the fraction)

what times 4  = 12? 3*4 = 12

11/4 * 3/3 = >33/12< (you multiply across)(3/3  = 1 so technically you arnt changing the value of the fraction)

32/12+33/12 = (32+33)all over 12

65/12<theres your answer in feet

5  5/12 feet  (12 inches is a foot so tecnically you are 5 inches in to the foot with that 5/12 soo...)

5 feet and 5 inches

Step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.