7. Figure 2 shows a mass P of 2.6kg, freely suspended by two strings AP and BP, fixed at two points A and B on the same horizontal plane. AB is 13 m. BP is perpendicular to AP. BP is an elastina
string of natural length lm, while AP is an inelastic string of natural length 0.5m. P hangs in
equilibrium when BP is 1.2m.
244
A
B
y=xtanx-go
Р
I= ft = F(V2_Y,
R=u2g in 24
9
Figure 2
Taking g = 10msfind
(a) the tension in each of the strings
(b) the modulus of elasticity of BP.
(6marks)
(marks)​

answer: your gay

step-by-step explanation:

you dont know math

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.