The profile of a section of roller coaster track is given by the equation h(x) = (2500+500sin(10pix))/x , X E [100,400], where h is the height of the track, in metres, and x is horizontal position, in metres.
a) Calculate the steepness (slope) of the track at the initial horizontal position.

x^5/3y^1/3 the correct answer

hope it

24

step-by-step explanation:

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)