Please answer quickly, just an assignment. Will mark brainliest if right

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Step-by-step explanation:

Let's call the weight of the large boxes:

l

Let's call the weight of the small boxes:

s

From the information in the equation we can now write two equations:

Equation 1:

5

l

+

3

s

=

99

Equation 2:

7

l

+

9

s

=

171

Step 1) Solve each equation for

9

s

:

Equation 1:

5

l

+

3

s

=

99

5

l

−

5

l

+

3

s

=

99

−

5

l

0

+

3

s

=

99

−

5

l

3

s

=

99

−

5

l

3

×

3

s

=

3

(

99

−

5

l

)

9

s

=

(

3

×

99

)

−

(

3

×

5

l

)

9

s

=

297

−

15

l

Equation 1:

7

l

+

9

s

=

171

7

l

−

7

l

+

9

s

=

171

−

7

l

0

+

9

s

=

171

−

7

l

9

s

=

171

−

7

l

Step 2) Because the left side of both equations are equivalent or the same we can equate the right side of each equation and solve for

l

:

297

−

15

l

=

171

−

7

l

297

−

171

−

15

l

+

15

l

=

171

−

171

−

7

l

+

15

l

126

−

0

=

0

+

(

−

7

+

15

)

l

126

=

8

l

126

8

=

8

l

8

15.75

=

8

l

8

15.75

=

l

l

=

15.75

Step 3) Substitute

15.75

for

l

in the solution to either equation in Step 1 and solve for

s

:

9

s

=

297

−

15

l

becomes:

9

s

=

297

−

(

15

×

15.75

)

9

s

=

297

−

236.25

9

s

=

60.75

9

s

9

=

60.75

9

9

s

9

=

6.75

s

=

6.75

The Solution Is:

The large boxes weigh 15.75 Kg

Step-by-step explanation:

step-by-step explanation:

compare

step-by-step explanation:

two pairs of adjacent sides are of equal length. this implies that one diagonal divides the kite into congruent triangles, and so the angles between the two pairs of equal sides are equal in measure. it also implies that the diagonals are perpendicular.