Two fair cubical dice are tossed. What is the probability that the sum of the numbers showing on the dice will be four?

1/36

Step-by-step explanation:

since a dice has 6 side and you want to get the probability of one of the dice it would be 1/6. But you have 2 dice and you need them both to have a 4.so you would need to multiply 1/6 by 1/6.

Im pretty sure this is right, its been a while since i did probability, but i hope this helps :)