Veronikas five test scores are 59 80 95 and 93 if the outlier of 59 is removed what is the mean absolute deviation of the remaining four test scores?

Complete Question

Veronikas four test scores are 59, 80, 95, 88 and 93 if the outlier of 59 is removed what is the mean absolute deviation of the remaining four test scores?

5

Step-by-step explanation:

We have the four test scores

80, 95, 88 and 93

Step 1

We find the mean of the 4 test scores

= 80 + 95 + 88 + 93/4

= 356 / 4

89

Step 2

The formula for Mean Absolute Deviation =

Summation( x - Mean)/n

Hence,

|(80 - 89 )+( 95 - 89) + (88 - 89) + (93 - 89)|/5

= 9 + 6 +1 + 4/4

= 20/4

= 5

the least common denominator is 40

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.