If an object is projected upward with an initial velocity of 125 ft per sec, its height h after t seconds is h= - 16t+ 125t. Find the height of the object after 2 seconds.​

h(t) = -16t^2+125t

We need to find h(t) when t = 4 s:

h(4) = -16*4^2+125*4

h(4) = 244 ft

The height of the object after 4 seconds is 244 feet.

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.