the area of a rectangle is 96m^2 and the circumference is 39.2m. Determine the dimensions if the rectangle​

Dimension => 10 m × 9.6 m

Step-by-step explanation:

From the question given above, the following data were obtained:

Area (A) = 96 m²

Circumference (C) = 39.2 m

Dimension =.?

Next, we shall determine the Lenght and breadth of the rectangle. This can be obtained as follow:

Let L be the Lenght

Let B be the breadth

Area of a rectangle = L × B

96 = L × B (1)

Circumference of rectangle = 2(L + B)

39.2 = 2(L + B) (2)

From equation 2, make L the subject

39.2 = 2(L + B)

Divide both side by 2

39.2 /2 = L + B

19.6 = L + B

Rearrange

L = 19.6 – B (3)

Substitute the value of L in equation 3 into equation 1

96 = L × B

L = 19.6 – B

96 = (19.6 – B ) × B

Clear bracket

96 = 19.6B – B²

Rearrange

B² – 19.6B + 96 = 0

Solving by factorisation

B² – 10B – 9.6B + 96 = 0

B(B – 10) – 9.6(B – 10) = 0

(B – 9.6)(B – 10) = 0

B – 9.6 = 0 or B – 10 = 0

B = 9.6 or B = 10

Substitute the value of B into equation 3:

L = 19.6 – B

B = 9.6

L = 19.6 – 9.6

L = 10

Or

L = 19.6 – B

B = 10

L = 19.6 – 10

L = 9.6

Since the length is always longer than the breadth,

Length (L) = 10 m

Breadth (B) = 9.6 m

Finally, we shall determine the dimension of the rectangle. This can be obtained as follow:

Length (L) = 10 m

Breadth (B) = 9.6 m

Dimension =?

Dimension = L × B

Dimension = 10 m × 9.6 m

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

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