Show that triangle BCD is isosceles

∠A = 36
∠C =36
∠ADB =72°
∠CBD =36°
∠BDC =108°

Explanation:

AB=AD then ∠ABD & ∠ADB must be equal as they share two lines that are equal so ∠ADB=72°

∠A and ∠C must also be equal (AB=BC)
∠A = 180-72-72=36°
So ∠A & ∠C=36°

∠D=180° (straight line)
So if ∠ADC=72
∠BDC=108° (180-72)

A triangle has 180° so in triangle BDC we have 108° and 36°
So remaining angle (∠CBD) =180-108-36
=36°

This tells us that triangle BDC is isosceles as it has two equal angles ∠CBD & ∠C =36°

I’m vary good with science if you need with that

Hmmm i had this before , give me a sec