find the time required for an investment of $3000 to grow to $8000 at an interest rate of 7.5% per year, compounded quarterly ( round the answer to two decimal places)​

8000 = 3000(1 + 0.065/4)4n

8000/3000 = (1 + 0.065/4)4n

ln(8000/3000) = 4nln(1 + 0.065/4)

n = ln(8000/3000)/4ln(1 + 0.065/4)

n = 15.21

$3,200 x 7.25% = $3,200 x .0725 = $232 interest monthly

$232 monthly x 12 annual = $2, 784

step-by-step explanation:

it would be 3 ÷by 6 because the number on each side