What is the recursive formula of the geometric sequence 1/2,3/4,9/8,27/16

Step-by-step explanation:

A recursive geometric formula has the pattern:

where r is the common ratio. Before we write the formula, we need to find the value for r. This r value has to be the same between each consecutive number in the series. Because it's geometric, r is multiplied in (whereas it's added in if the sequence is arithmetic). To get from 1/2 to 3/4 we find the r value in this way:

where x/2 is the same as 1/2 x. Cross multiply to get 4x = 6 and x = 3/2. That means that if r is 3/2, then we can multiply every term in that sequence by 3/2 to get to the next term in line. 3/4 times 32 is 9/8. Therefore, r = 3/2 and the formula will be:

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step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.