Algebra 2 Logarithms Problem

Given

log₃ 20 = x and log₃ 2 = y

Properties used

log ab = log a  + log blog a/b = log a - log blog aᵇ = b log a

a)

log₃ 400 = log₃ (20)² = 2 log₃ 20 = 2x

b)

log₃ 80 = log₃ (20*4) = log₃ 20 + log₃ 4 = log₃ 20 + 2log₃ 2 = x + 2y

c)

log₃ 40 = log₃ (20*2) = log₃ 20 + log₃ 2 = x + y

d)

log₃ 10 = log₃ (20/2) = log₃ 20 - log₃ 2 = x - y

9/12 is the answer because 3/4 times 3 each is 9/12