The perimeter of a square is 20. What is the length of one of the diagonals of the square? Show work or explain how you obtained your answer

The perimeter of a square is 20

if length of the square is x

perimeter of a square = x + x+ x + x = 4x = 20

4x = 20

x= 20/4

x = 5

Let get the length of one of the diagonal is y

According to the Pythagoras  low,

y^2 = x^2 + x^2

y^2 = 5^2 + 5^2

y^2 = 25 + 25

y^2 = 50

y= sqrt(50)

Step-by-step explanation: