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Mathematics, 29.03.2021 14:00 malachijwilson5

In ΔJKL, l = 380 cm, j = 620 cm and ∠K=30°. Find the area of ΔJKL, to the nearest square centimeter.

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In ΔJKL, l = 380 cm, j = 620 cm and ∠K=30°. Find the area of ΔJKL, to the nearest square centimeter....
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