Ayuda: A) [-3+(6-8)]-[40+(5.3-7)+20.2]=

B)-4+[-2.6-1-(-3.4)]+(-5).(-3)+(-10 )=

C)-22.{-5+[8.3-(3.6-9)]}-(-2).(3)=

D)-9-(-2+5).[-3+(-5)-(+2)+1]=

E)40.{-12.[4+(-6).(-5)-15.3+12]}-2=

F)-21.{-[-6.(7-3)]-(7.6-8.3)}-89=

Step-by-step explanation:

A) [-3+(6-8)] - [40+(5.3-7)+20.2]

= [-3+(-2)] - [40+(-1.7)+20.2]

= [-3-2] - [40-1.7+20.2]

= [-5] - [38.3+20.2]

= [-5] - [58.5]

= -5 - 58.5

= -63.5

B) -4+[-2.6-1-(-3.4)]+(-5).(-3)+(-10)]

= -4+[-3.6+3.4]+(-15)+(-10)

= -4+[-0.2]-15-10

= -4+[-0.2]-25.

= -4-0.2-25

= -4.2-25

= -29.2

C) -22{-5+[8.3-(3.6-9)]}-(-2)(3)

= -22{-5+[8.3-(-5.4)]}-(-2)(3)

= -22{-5+[8.3+5.4]}-(-2)(3)

= -22{-5+13.7}-(-6)

= -22{8.7}+6

= -191.4+6

= -185.4

D) -9-(-2+5).[-3+(-5)-(+2)+1]

= -9-(3)[-3+(-5)-(+2)+1]

= -9-3[-3+(-5)-(+2)+1]

= -12[-3+(-5)-(+2)+1]

= -12[-3-5-2+1]

= -12[-10+1]

= -12[-9]

= 108.

E) 40{-12[4+(-6)(-5)-15.3+12]}-2

= 40{-12[4+(-30)-15.3+12]}-2

= 40{-12[4-30-15.3+12]}-2

= 40{-12[-26-15.3+12]}-2

= 40{-12[-29.3]}-2

= 40{-12-29.3}-2

= 40{-41.3}-2

= 1652-2

= 1650.

F) -21{-[-6(7-3)]-(7.6-8.3)}-89

= -21{-[-6(4)]-(7.6-8.3)}-89

= -21{-[-24]-(7.6-8.3)}-89

= -21{24-(-0.7)}-89

= -21{24+0.7}-89

= -21{24.7}-89

= -518.7-89

= -607.7

correct answer:

i^31 = -i

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.