1. If p(q) = q2 + 4q - 12
what is p(-1)
How do I solve this and what is the answer?

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

explanation:

step-by-step explanation:

answer: x=1

step-by-step explanation:

f(x) = g(x)

x - 2 = -1

x = 1

therefore the graph should be a line showing x=1 which is vertical and passes on 1

hope it !

(4x+15)^2

step-by-step explanation:

factor using the perfect square rule