Can someone solve this, please?
when x€[0,2pi]​​

9514 1404 393

  x ∈ {{0.30773985, 1.26305647, 1.87853618, 2.83385280, 3.44933251, 4.40464913, 5.02012883, 5.97544545}

Step-by-step explanation:

Divide by the coefficient of the sine function, take the root, then use the arcsine function to find the angles.

The numerical values are approximately ...

  x ∈ {{0.30773985, 1.26305647, 1.87853618, 2.83385280, 3.44933251, 4.40464913, 5.02012883, 5.97544545}

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The graph shows the zeros of 3sin²(2x) -1.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}