Which of the following is the correct solution to the linear inequality shown bellow. Y>1/3x-2

Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?

Vip at (-2,7) dropped her pass and moved to the right on a slope of -9 where can you catch up to her to return her vip pass

Solve for x and y: 217x + 131y = 913; 131x + 217y = 827