Sarah took the advertising deparſment from her company on a round trip to meet with a potential client. Including Sarah a total of 11 people took the trip. She was able to purchase coach tickets for $240 and first class tickets for $1100. She used her total budget for airfare for the trip, which was $6080. How many first class
tickets did she buy? How many coach tickets did she buy?

Sarah bought 7 coach tickets and 4 first class tickets.

Step-by-step explanation:

From the information provided, you can write the following equations:

x+y=11 (1)

240x+1100y=6080 (2), where:

x is the number of coach tickets

y is the number of first class tickets

In order to find the value of x and y, first you have to solve for x in (1):

x=11-y (3)

Now, you have to replace (3) in (2) and solve for y:

240(11-y)+1100y=6080

2640-240y+1100y=6080

860y=6080-2640

860y=3440

y=3440/860

y=4

Finally, you can replace the value of y in (3) to find the value of x:

x=11-y

x=11-4

x=7

According to this, the answer is that Sarah bought 7 coach tickets and 4 first class tickets.

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.