Use Substitution to solve the following System of Equations.
y=-22 - 4
y = 4x + 2
Oh

X=4

Y=18

I think

(- 1, - 2 )

Step-by-step explanation:

Given the 2 equations

y = - 2x - 4 → (1)

y = 4x + 2 → (2)

Substitute y = 4x + 2 into (1)

4x + 2 = - 2x - 4 ( add 2x to both sides )

6x + 2 = - 4 ( subtract 2 from both sides )

6x = - 6 ( divide both sides by 6 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (2)

y = 4(- 1) + 2 = - 4 + 2 = - 2

solution is (- 1, - 2 )

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.