An isotope of cesium-137 has a half-life of 30 years. If 5.5 grams of cesium-137 disintigrates over a period of 105 years, how many grams of cesium-137 would remain? Round your answer to the thousandths place.

0.484 g

Step-by-step explanation:

N/No = (1/2)^t/t1/2

No = mass of cesium-137 originally present

N= mass of cesium-137 at time t

t1/2= half life of cesium-137

t = time taken

N/5.5=(1/2)^105/30

N/5.5=(1/2)^3.5

N/5.5= 0.088

N = 5.5 *  0.088

N= 0.484 g

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00