C. Find the equation that is parallel to y = 12x-2 and crosses the point (6,2)

The equation of line a is y=(1/2)x−1, and it passes through point (6,2).

       line b is: y = -2x + c and we use point (-6,2) to find b.

      2 = -2(-6) + c

     14 = c

The equation for line b is: y = -2x + 14

The y-intercept (which is the point where x=0) is the point (0,14.)        So, y=14

Step-by-step explanation:

hope this helps       :)

depends on how many days you are talking about

step-by-step explanation:

is should be y = 5x

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correct me if im wrong