Drag the tiles to the correct boxes to complete the pairs

Hi i’m not sure how to do question 20 if u could explain how to do it that’d b great

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)

Which of the following is not a solution to the inequality graphed below? (-2, -4)(-1, -5)(0, -3)(2, -1)which of the following is a solution to the inequality graphed below? select all that apply.(-3, -3)(-1, -1)(-3, -1)(2, 2)