the diagram represents a sports ground. the bends are semicircle. calculate the area of the sports ground. give your answer correct to the nearest square metre

8,163 square meter

Step-by-step explanation:

The area of the sports ground = area of rectangle + 2(area of semicircles)

= L*W + 2(½*πr²)

L = 120 m

W = 51 m

r = ½ of 51 = 25.5 m

Plug in the values

Area of the sports ground = 120*51 + 2(½*π*25.5²)

Area = 6,120 + 2,042.82062

Area = 8,162.82062 ≈ 8,163 square meter

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).