You randomly choose a tile. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing two even numbers is

Complete question :

You randomly choose a tile. Without replacing the first tile, you choose a second tile. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth. The probability of choosing two even numbers is

Tiles : 7,6, 5, 8, 9, 10, 20

2 /7

Step-by-step explanation:

The probability of a compound event in the scenario described above :

P(1st pick) * p(second pick)

Recall: this event is without replacement

P(choosing two even numbers)

Probability = required outcome / Total possible outcomes

Required outcome = even Number tiles = (6, 8, 10, 20) = 4

Total possible outcomes = number of tiles = 7

P(even number on first pick) = 4/7

P(even on second pick) = 3 / 6 = 1/2

P(compound event) = 4/7 * 1 /2 = 4 /14 = 2 /7

(23*2)-12=x     x=34

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺